洛谷 P2015 二叉苹果树

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#include <bits/stdc++.h>
using namespace std;
const int N = 101, M = 202;
int u, v, ww, h[N], e[M], ne[M], w[M], idx;
int n, t;
int dp[N][N];
void add(int u, int v, int ww) {
e[++idx] = v, w[idx] = ww, ne[idx] = h[u], h[u] = idx;
}
int dfs(int u, int f) {
int sum = 0;
for (int i = h[u]; i; i = ne[i]) {
int v = e[i];
if (v == f) continue;
int s = dfs(v, u);
sum += s + 1;
for (int j = min(sum, t); j; --j)
for (int k = min(s, j - 1); k >= 0; --k)
dp[u][j] = max(dp[u][j], dp[v][k] + dp[u][j - k - 1] + w[i]);
}
return sum;
}
int main() {
scanf("%d%d", &n, &t);
for (int i = 1; i < n; ++i) {
scanf("%d%d%d", &u, &v, &ww);
add(u, v, ww);
add(v, u, ww);
}
dfs(1, 0);
printf("%d\n", dp[1][t]);
return 0;
}