洛谷 P3834 【模板】可持久化线段树 2

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
#include <cstdio>
#include <algorithm>
using namespace std;
const int N = 200001;
int n, m, a[N], nums[N], root[N], idx, l, r, k, len;
struct Node {
int l, r, cnt;
} tr[N * 4 + N * 18];
int find(int x) {
return lower_bound(nums + 1, nums + 1 + len, x) - nums;
}
int build(int l, int r) {
int p = ++idx;
if (l == r) return p;
int mid = (l + r) >> 1;
tr[p].l = build(l, mid), tr[p].r = build(mid + 1, r);
return p;
}
int insert(int p, int l, int r, int x) {
int q = ++idx;
tr[q] = tr[p];
if (l == r) {
++tr[q].cnt;
return q;
}
int mid = (l + r) >> 1;
if (x <= mid) tr[q].l = insert(tr[p].l, l, mid, x);
else tr[q].r = insert(tr[p].r, mid + 1, r, x);
tr[q].cnt = tr[tr[q].l].cnt + tr[tr[q].r].cnt;
return q;
}
int query(int q, int p, int l, int r, int k) {
if (l == r) return r;
int cnt = tr[tr[q].l].cnt - tr[tr[p].l].cnt, mid = (l + r) >> 1;
if (k <= cnt) return query(tr[q].l, tr[p].l, l, mid, k);
return query(tr[q].r, tr[p].r, mid + 1, r, k - cnt);
}
int main() {
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i) {
scanf("%d", &a[i]);
nums[i]= a[i];
}
sort(nums + 1, nums + 1 + n);
len = unique(nums + 1, nums + 1 + n) - nums - 1;
root[0] = build(1, len + 1);
for (int i = 1; i <= n; ++i)
root[i] = insert(root[i - 1], 1, len, find(a[i]));
while (m--) {
scanf("%d%d%d", &l, &r, &k);
printf("%d\n", nums[query(root[r], root[l - 1], 1, len, k)]);
}
return 0;
}