LeetCode 1006. Clumsy Factorial

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class Solution {
public:
int clumsy(int N) {
stack<int> stk;
stk.push(N--);
int idx = -1;
while (N) {
switch (idx = ++idx % 4) {
case 0:
stk.top() *= N--;
break;
case 1:
stk.top() /= N--;
break;
case 2:
stk.push(N--);
break;
case 3:
stk.push(-(N--));
}
}
int sum = 0;
while (!stk.empty()) {
sum += stk.top();
stk.pop();
}
return sum;
}
};