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Shawn

若有恒,何必三更眠五更起;最无益,莫过一日曝十日寒。
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LeetCode 1829. Maximum XOR for Each Query

Posted on 2021-04-18 Edited on 2024-11-24 In LeetCode
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class Solution {
public:
vector<int> getMaximumXor(vector<int>& nums, int maximumBit) {
int n = nums.size(), mask = 0, target = (1 << maximumBit) - 1;
vector<int> ans(n);
for (int num : nums) {
mask ^= num;
ans[--n] = (mask ^ target);
}
return ans;
}
};
# Bit Manipulation
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LeetCode 27. Remove Element
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