LeetCode 947. Most Stones Removed with Same Row or Column

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class Solution {
public:
int removeStones(vector<vector<int>>& stones) {
const int n = stones.size();
vector<vector<int>> edges(n);
for (int i = 0; i < n; ++i)
for (int j = 0; j < n; ++j)
if ((stones[i][0] == stones[j][0]) || (stones[i][1] == stones[j][1]))
edges[i].emplace_back(j);
vector<bool> visited(n);
function<void(int)> dfs = [&](int x) {
visited[x] = true;
for (const int y : edges[x])
if (!visited[y])
dfs(y);
};
int cnt = 0;
for (int i = 0; i < n; ++i)
if (!visited[i]) {
++cnt;
dfs(i);
}
return n - cnt;
}
};
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class Solution {
public:
int removeStones(vector<vector<int>>& stones) {
const int n = stones.size();
unordered_map<int, vector<int>> m;
for (int i = 0; i < n; ++i) {
m[stones[i][0]].emplace_back(i);
m[stones[i][1] + 10000].emplace_back(i);
}
vector<vector<int>> edges(n);
for (const auto& [_, vec] : m) {
const int k = vec.size();
for (int i = 1; i < k; ++i) {
edges[vec[i - 1]].emplace_back(vec[i]);
edges[vec[i]].emplace_back(vec[i - 1]);
}
}
vector<bool> visited(n);
function<void(int)> dfs = [&](int x) {
visited[x] = true;
for (const int y : edges[x])
if (!visited[y])
dfs(y);
};
int cnt = 0;
for (int i = 0; i < n; ++i)
if (!visited[i]) {
++cnt;
dfs(i);
}
return n - cnt;
}
};
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class DisjointSetUnion {
private:
unordered_map<int, int> f, rank;
public:
int find(int x) {
if (f.find(x) == f.end()) {
f[x] = x;
rank[x] = 1;
}
return f[x] == x ? x : f[x] = find(f[x]);
}
void unionSet(int x, int y) {
int fx = find(x), fy = find(y);
if (fx != fy) {
if (rank[fx] > rank[fy])
swap(fx, fy);
rank[fy] += rank[fx];
f[fx] = fy;
}
}
int numberOfConnectedComponent() {
int cnt = 0;
for (auto &[x, fa] : f)
if (x == fa)
++cnt;
return cnt;
}
};
class Solution {
public:
int removeStones(vector<vector<int>> &stones) {
const int n = stones.size();
DisjointSetUnion dsu;
for (int i = 0; i < n; ++i)
dsu.unionSet(stones[i][0], stones[i][1] + 10000);
return n - dsu.numberOfConnectedComponent();
}
};